What is the first derivative of 3x^2-6 ?

The first derivative of 3x^2-6 is 6x

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derivative of 3x^2-6

derivative of

3 x^{2} - 6

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6) = 0

= 6 x - 0

Simplify

= 6 x

\int (x - 1)^{2} e^{x} d x

\int tan (2 θ) d θ

(y^{4} - 2 x y) d x + 3 x^{2} d y = 0

\frac{d y}{d x} = \frac{8 e ^{4 x}}{2 cos ( 2 y )}

arcsec (x) - 6 x