What is the solution for (y^4-2xy)dx+3x^2dy=0 ?

The solution for (y^4-2xy)dx+3x^2dy=0 is y=\sqrt[3]{(x^2)/(x+c_{1)}}

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(y^4-2xy)dx+3x^2dy=0

(y^{4} - 2 x y) d x + 3 x^{2} d y = 0

y = 3 \frac{x ^{2}}{x + c _{1}}

Solution steps

(y^{4} - 2 x y) d x + 3 x^{2} d y = 0

Solve Bernoulli ODE:

y = 3 \frac{x ^{2}}{x + c _{1}}

y = 3 \frac{x ^{2}}{x + c _{1}}

\frac{d y}{d x} = \frac{8 e ^{4 x}}{2 cos ( 2 y )}

arcsec (x) - 6 x

\frac{d}{d x} (3 x^{2} - 2 x + 5)

\frac{1}{3 x + 5}

\int_{0}^{1} x^{2} e^{- x^{2}} d x

What is the solution for (y^4-2xy)dx+3x^2dy=0 ?
The solution for (y^4-2xy)dx+3x^2dy=0 is y=\sqrt[3]{(x^2)/(x+c_{1)}}