What is the derivative of arcsec(x)-6x ?

The derivative of arcsec(x)-6x is 1/(sqrt(x^2)\sqrt{x^2-1)}-6

What is the first derivative of arcsec(x)-6x ?

The first derivative of arcsec(x)-6x is 1/(sqrt(x^2)\sqrt{x^2-1)}-6

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derivative of

arcsec (x) - 6 x

\frac{1}{x ^{2} x ^{2} - 1} - 6

Solution steps

\frac{d}{d x} (arcsec (x) - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arcsec (x)) - \frac{d}{d x} (6 x)

\frac{d}{d x} (arcsec (x)) = \frac{1}{x ^{2} x ^{2} - 1}

\frac{d}{d x} (6 x) = 6

= \frac{1}{x ^{2} x ^{2} - 1} - 6

\frac{d}{d x} (3 x^{2} - 2 x + 5)

\frac{1}{3 x + 5}

\int_{0}^{1} x^{2} e^{- x^{2}} d x

\frac{\partial ^{2}}{\partial x ^{2}} (arctan (\frac{y}{x}))

\int \frac{x ^{2} - 1}{x} d x

What is the derivative of arcsec(x)-6x ?
The derivative of arcsec(x)-6x is 1/(sqrt(x^2)\sqrt{x^2-1)}-6
What is the first derivative of arcsec(x)-6x ?
The first derivative of arcsec(x)-6x is 1/(sqrt(x^2)\sqrt{x^2-1)}-6