What is the integral of (x^2-1)/(sqrt(x)) ?

The integral of (x^2-1)/(sqrt(x)) is 2/5 x^{5/2}-2sqrt(x)+C

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integral of (x^2-1)/(sqrt(x))

\int \frac{x ^{2} - 1}{x} d x

\frac{2}{5} x^{\frac{5}{2}} - 2 x + C

Solution steps

\int \frac{x ^{2} - 1}{x} d x

Expand

\frac{x ^{2} - 1}{x} : x^{\frac{3}{2}} - \frac{1}{x}

= \int x^{\frac{3}{2}} - \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x - \int \frac{1}{x} d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int \frac{1}{x} d x = 2 x

= \frac{2}{5} x^{\frac{5}{2}} - 2 x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} - 2 x + C

x \to 2 lim (\frac{1}{x ( x ^{2} - 2 )})

\frac{d y}{d x} = \frac{2 x y}{x ^{2} - y ^{2}}, y (1) = 1

\frac{6}{( s ^{3} - 2 ) ^{3}}

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

y = - x^{2} + 4, y = - \frac{x ^{2}}{2} + 2

What is the integral of (x^2-1)/(sqrt(x)) ?
The integral of (x^2-1)/(sqrt(x)) is 2/5 x^{5/2}-2sqrt(x)+C