What is longdivision (x^2-5x)/(x+1) ?

The solution to longdivision (x^2-5x)/(x+1) is x-6+6/(x+1)

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longdivision (x^2-5x)/(x+1)

long division

\frac{x ^{2} - 5 x}{x + 1}

x - 6 + \frac{6}{x + 1}

Solution steps

\frac{x ^{2} - 5 x}{x + 1}

Divide

\frac{x ^{2} - 5 x}{x + 1} : \frac{x ^{2} - 5 x}{x + 1} = x + \frac{- 6 x}{x + 1}

= x + \frac{- 6 x}{x + 1}

Divide

\frac{- 6 x}{x + 1} : \frac{- 6 x}{x + 1} = - 6 + \frac{6}{x + 1}

= x - 6 + \frac{6}{x + 1}

(t - 2)^{3} (t - 2)

y^{^{'}} = \frac{( x ^{3} - 2 y )}{x}

\frac{d}{d x} (6 sin (2 x) - 3 cos (3 x))

\frac{d}{d x} (- 536870912 sin (2 x))

f (x) = 10 + x

What is longdivision (x^2-5x)/(x+1) ?
The solution to longdivision (x^2-5x)/(x+1) is x-6+6/(x+1)