What is the derivative of (4x)/(sqrt(x^2+2)) ?

The derivative of (4x)/(sqrt(x^2+2)) is 8/((x^2+2)sqrt(x^2+2))

What is the first derivative of (4x)/(sqrt(x^2+2)) ?

The first derivative of (4x)/(sqrt(x^2+2)) is 8/((x^2+2)sqrt(x^2+2))

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derivative of

\frac{4 x}{x ^{2} + 2}

\frac{8}{( x ^{2} + 2 ) x ^{2} + 2}

Solution steps

\frac{d}{d x} (\frac{4 x}{x ^{2} + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x ^{2} + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} x ^{2} + 2 - \frac{d}{d x} ( x ^{2} + 2 ) x}{( x ^{2} + 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 2) = \frac{x}{x ^{2} + 2}

= 4 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}} : \frac{8}{( x ^{2} + 2 ) x ^{2} + 2}

= \frac{8}{( x ^{2} + 2 ) x ^{2} + 2}

\frac{\partial}{\partial x} (x (10 - x - y))

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} = 12 cos (2 x)

\int \frac{6 - 6 x}{1 - x} d x

y = 3 x^{2} + 1, (0, - 1)

y^{^{''}} - 7 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

What is the derivative of (4x)/(sqrt(x^2+2)) ?
The derivative of (4x)/(sqrt(x^2+2)) is 8/((x^2+2)sqrt(x^2+2))
What is the first derivative of (4x)/(sqrt(x^2+2)) ?
The first derivative of (4x)/(sqrt(x^2+2)) is 8/((x^2+2)sqrt(x^2+2))