What is the tangent of 3x^2-6x+5 ?

The tangent of 3x^2-6x+5 is y=(6a_{0}-6)x-3a_{0}^2+5

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tangent of 3x^2-6x+5

tangent of

3 x^{2} - 6 x + 5

y = (6 a_{0} - 6) x - 3 a_{0}^{2} + 5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 6 a_{0} + 5)

Find the slope of

y = 3 x^{2} - 6 x + 5 : \frac{d y}{d x} = 6 x - 6

Compute the slope of

y = 3 x^{2} - 6 x + 5

x = a_{0} : m = 6 a_{0} - 6

Find the line with slope m=

6 a_{0} - 6

and passing through

(a_{0}, 3 a_{0}^{2} - 6 a_{0} + 5) : y = (6 a_{0} - 6) x - 3 a_{0}^{2} + 5

y = (6 a_{0} - 6) x - 3 a_{0}^{2} + 5

\int \frac{cos ( x )}{1 + 2 sin ( x )} d x

\frac{d}{d x} (e^{l n (x^{2})})

x \to 0 lim (\frac{1}{x ^{3}})

\frac{d}{d x} (\frac{x}{( 1 - x ) ^{2}})

f (x) = \frac{7}{r ^{3}}

What is the tangent of 3x^2-6x+5 ?
The tangent of 3x^2-6x+5 is y=(6a_{0}-6)x-3a_{0}^2+5