What is the integral of 3x^2-24x+48 ?

The integral of 3x^2-24x+48 is x^3-12x^2+48x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3x^2-24x+48

\int 3 x^{2} - 24 x + 48 d x

x^{3} - 12 x^{2} + 48 x + C

Solution steps

\int 3 x^{2} - 24 x + 48 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 24 x d x + \int 48 d x

\int 3 x^{2} d x = x^{3}

\int 24 x d x = 12 x^{2}

\int 48 d x = 48 x

= x^{3} - 12 x^{2} + 48 x

Add a constant to the solution

= x^{3} - 12 x^{2} + 48 x + C

\int \frac{x ^{2} - 7 x - 12}{x ( x ^{2} + 3 x + 3 )} d x

\frac{d}{d x} (3 x^{4} - 8 x^{3} + 2)

f (x) = - 5 x^{2} - 6 x + 200

lo g_{6} (x)

y^{^{''}} + 2 t = 0

What is the integral of 3x^2-24x+48 ?
The integral of 3x^2-24x+48 is x^3-12x^2+48x+C