What is (\partial)/(\partial y)(5xsin(y-z)) ?

The answer to (\partial)/(\partial y)(5xsin(y-z)) is 5xcos(y-z)

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(\partial)/(\partial y)(5xsin(y-z))

\frac{\partial}{\partial y} (5 x sin (y - z))

5 x cos (y - z)

Solution steps

\frac{\partial}{\partial y} (5 x sin (y - z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 x \frac{\partial}{\partial y} (sin (y - z))

Apply the chain rule:

cos (y - z) \frac{\partial}{\partial y} (y - z)

= cos (y - z) \frac{\partial}{\partial y} (y - z)

\frac{\partial}{\partial y} (y - z) = 1

= 5 x cos (y - z) \cdot 1

Simplify

= 5 x cos (y - z)

\frac{d}{d x} ((7 x^{2} - 12 x) e^{x})

y^{^{'}} - e^{5 x + y} = 0

e^{y} + \frac{( x e ^{y} + 1 ) d y}{d x} = 0

\frac{d}{d x} (\frac{3 x + 2}{5 x - 1})

x \to - 4 lim (\frac{2}{( x + 4 ) ^{3}})

What is (\partial)/(\partial y)(5xsin(y-z)) ?
The answer to (\partial)/(\partial y)(5xsin(y-z)) is 5xcos(y-z)