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Popular >

y^'-e^{5x+y}=0

Solution

y^{^{'}} - e^{5 x + y} = 0

Solution

y = - ln (- \frac{1}{5} e^{5 x} - c_{1})

Solution steps

y^{'} (x) - e^{5 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{5} e^{5 x} - c_{1})

y = - ln (- \frac{1}{5} e^{5 x} - c_{1})

Popular Examples

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x \to - 4 lim (\frac{2}{( x + 4 ) ^{3}})

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\frac{d}{d x} (6 + 3 x - 4 x (7 x + 1)^{2})

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Frequently Asked Questions (FAQ)

What is the solution for y^'-e^{5x+y}=0 ?
The solution for y^'-e^{5x+y}=0 is y=-ln(-1/5 e^{5x}-c_{1})