What is the solution for y^{''}+y=4x+10 ?

The solution for y^{''}+y=4x+10 is y=c_{1}cos(x)+c_{2}sin(x)+4x+10

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y^{''}+y=4x+10

y^{^{''}} + y = 4 x + 10

y = c_{1} cos (x) + c_{2} sin (x) + 4 x + 10

Solution steps

y^{''} (x) + y = 4 x + 10

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + 4 x + 10

y = c_{1} cos (x) + c_{2} sin (x) + 4 x + 10

x y^{^{'}} = y + x^{2} - y^{2}

x \to 1 - lim (\frac{5}{x ^{3} - 1})

f (x) = 4 x^{2} - 2 x + 1, at x = 3

1 + e^{x}

\int - x cos (2 x) d x

What is the solution for y^{''}+y=4x+10 ?
The solution for y^{''}+y=4x+10 is y=c_{1}cos(x)+c_{2}sin(x)+4x+10