What is the derivative of 4x^3+3x^2 ?

The derivative of 4x^3+3x^2 is 12x^2+6x

What is the first derivative of 4x^3+3x^2 ?

The first derivative of 4x^3+3x^2 is 12x^2+6x

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\frac{d}{d x} (4 x^{3} + 3 x^{2})

12 x^{2} + 6 x

Solution steps

\frac{d}{d x} (4 x^{3} + 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

= 12 x^{2} + 6 x

\int sin (x) + 5 d x

\int \frac{ln ( x )}{16} d x

\frac{d}{d x} ((3 - 4 x) e^{- 2 x^{2}})

\frac{d}{d x} (\frac{x ^{3} - 3 x ^{2} + 4 x - 5}{x ^{2}})

x \to - \infty lim (8^{x})

What is the derivative of 4x^3+3x^2 ?
The derivative of 4x^3+3x^2 is 12x^2+6x
What is the first derivative of 4x^3+3x^2 ?
The first derivative of 4x^3+3x^2 is 12x^2+6x