What is the solution for f^'(x)=-4x^3+2x^2-7 ?

The solution for f^'(x)=-4x^3+2x^2-7 is f(x)=-x^4+(2x^3)/3-7x+c_{1}

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f^'(x)=-4x^3+2x^2-7

f^{^{'}} (x) = - 4 x^{3} + 2 x^{2} - 7

f (x) = - x^{4} + \frac{2 x ^{3}}{3} - 7 x + c_{1}

Solution steps

f^{'} (x) = - 4 x^{3} + 2 x^{2} - 7

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int - 4 x^{3} + 2 x^{2} - 7 d x

\int - 4 x^{3} + 2 x^{2} - 7 d x = - x^{4} + \frac{2 x ^{3}}{3} - 7 x + c_{1}

f (x) = - x^{4} + \frac{2 x ^{3}}{3} - 7 x + c_{1}

f (x) = x + 2 cos (x), at x = 0

y = 3 x^{3} - 2 x, (- 1, - 1)

\int - 0.2 x + 43 d x

\frac{7 + 2 x}{9 - 8 x}

\frac{d}{d x} ((4 + 3 x)^{2})

What is the solution for f^'(x)=-4x^3+2x^2-7 ?
The solution for f^'(x)=-4x^3+2x^2-7 is f(x)=-x^4+(2x^3)/3-7x+c_{1}