What is the tangent of f(x)=x^2-x,\at x=-2 ?

The tangent of f(x)=x^2-x,\at x=-2 is y=-5x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-x,\at x=-2

tangent of

f (x) = x^{2} - x, at x = - 2

y = - 5 x - 4

Solution steps

Find the tangent point:

(- 2, 6)

Find the slope of

f (x) = x^{2} - x : \frac{df ( x )}{d x} = 2 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 6) : y = - 5 x - 4

y = - 5 x - 4

\int_{0}^{0.5} (- 13 x + 6) - (- x) d x

\int \frac{3}{5 x - 1} d x

\int_{0}^{2} (x 4 - x^{2}) d x

\frac{d}{d x} (2 + 3 x)

- 2 x^{2} + 8, 3 x + 1, 0

What is the tangent of f(x)=x^2-x,\at x=-2 ?
The tangent of f(x)=x^2-x,\at x=-2 is y=-5x-4