What is area y=x^3-10x^2+21x,y=-x^3+10x^2-21x ?

The answer to area y=x^3-10x^2+21x,y=-x^3+10x^2-21x is 937/6

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area y=x^3-10x^2+21x,y=-x^3+10x^2-21x

area

y = x^{3} - 10 x^{2} + 21 x, y = - x^{3} + 10 x^{2} - 21 x

\frac{937}{6}

Decimal Notation

156.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{7} x^{3} - 10 x^{2} + 21 x - (- x^{3} + 10 x^{2} - 21 x) d x

Solve

\int_{0}^{7} x^{3} - 10 x^{2} + 21 x - (- x^{3} + 10 x^{2} - 21 x) d x : \frac{937}{6}

The area is:

= \frac{937}{6}

e^{\frac{3}{x}}

y^{^{''}} - y = \frac{2 e ^{- x}}{( 1 + e ^{- 2 x} ) ^{2}}

\frac{d y}{d x} + \frac{x y}{x ^{2} + 1} = \frac{x}{x ^{2} + 1}

n \to \infty lim (- 3^{- n})

\int \frac{1}{x + 1} d x

What is area y=x^3-10x^2+21x,y=-x^3+10x^2-21x ?
The answer to area y=x^3-10x^2+21x,y=-x^3+10x^2-21x is 937/6