What is the derivative of (2x-1/x) ?

The derivative of (2x-1/x) is 1/(x^2)

What is the first derivative of (2x-1/x) ?

The first derivative of (2x-1/x) is 1/(x^2)

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\frac{d}{d x} (\frac{2 x - 1}{x})

\frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) x - \frac{d x}{d x} ( 2 x - 1 )}{x ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d x}{d x} = 1

= \frac{2 x - 1 \cdot ( 2 x - 1 )}{x ^{2}}

Simplify

= \frac{1}{x ^{2}}

\int \frac{1}{- cos ( u ) + 1} d u

\frac{\partial}{\partial y} ((2 x - 3 y)^{3})

\int - csc (x) cot (x) d x

\int (x^{2} + 1)^{- \frac{1}{2}} d x

(x + 6)^{2}

What is the derivative of (2x-1/x) ?
The derivative of (2x-1/x) is 1/(x^2)
What is the first derivative of (2x-1/x) ?
The first derivative of (2x-1/x) is 1/(x^2)