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Popular >

area-x+4,2x,x

Solution

area

- x + 4, 2 x, x

Solution

\frac{4}{3}

+1

Decimal Notation

1.33333 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- x + 4 = 2 x : x = \frac{4}{3}

- x + 4 = x : x = 2

2 x = x : x = 0

= \int_{0}^{\frac{4}{3}} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{\frac{4}{3}}^{2} ∣ f_{1} (x) - f_{3} (x) ∣ d x

= \int_{0}^{\frac{4}{3}} ∣ 2 x - x ∣ d x + \int_{\frac{4}{3}}^{2} ∣ - x + 4 - x ∣ d x

\int_{0}^{\frac{4}{3}} ∣ 2 x - x ∣ d x = \frac{8}{9}

\int_{\frac{4}{3}}^{2} ∣ - x + 4 - x ∣ d x = \frac{4}{9}

= \frac{8}{9} + \frac{4}{9}

Simplify

= \frac{4}{3}

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\int_{4}^{9} 4 x d x

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\frac{\partial}{\partial x} (x^{2} \frac{1}{a ^{2}})

integral of (13x^3)/(sqrt(7+x^2))

\int \frac{13 x ^{3}}{7 + x ^{2}} d x

integral of (3x^2+4x-4)

\int (3 x^{2} + 4 x - 4) d x

Frequently Asked Questions (FAQ)

What is area-x+4,2x,x ?
The answer to area-x+4,2x,x is 4/3