What is the derivative of-4x^2+x+5 ?

The derivative of-4x^2+x+5 is -8x+1

What is the first derivative of-4x^2+x+5 ?

The first derivative of-4x^2+x+5 is -8x+1

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\frac{d}{d x} (- 4 x^{2} + x + 5)

- 8 x + 1

Solution steps

\frac{d}{d x} (- 4 x^{2} + x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= - 8 x + 1 + 0

Simplify

= - 8 x + 1

x \to π - lim (ln (sin (x)))

f (x) = 9 x e^{x}

\frac{\partial}{\partial x} (6 y x^{5} - 12 y^{2} x^{2})

\int \frac{m ^{3}}{( m ^{2} + 1 ) ^{3}} d m

(- 2, 5), (2, - 7)

What is the derivative of-4x^2+x+5 ?
The derivative of-4x^2+x+5 is -8x+1
What is the first derivative of-4x^2+x+5 ?
The first derivative of-4x^2+x+5 is -8x+1