What is derivative of f(x)=(e^x)/(x^2+4),x=1 ?

The answer to derivative of f(x)=(e^x)/(x^2+4),x=1 is (3e)/(25)

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derivative of f(x)=(e^x)/(x^2+4),x=1

derivative of

f (x) = \frac{e ^{x}}{x ^{2} + 4}, x = 1

\frac{3 e}{25}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{x ^{2} + 4}) = \frac{e ^{x} ( x ^{2} + 4 ) - 2 x e ^{x}}{( x ^{2} + 4 ) ^{2}}

Find the value of

\frac{e ^{x} ( x ^{2} + 4 ) - 2 x e ^{x}}{( x ^{2} + 4 ) ^{2}}

for

x = 1 : \frac{3 e}{25}

\frac{3 e}{25}

f (x) = \frac{x + 1}{x - 2}

\int 0 d x

x^{4} - 3 x^{3} + 2 x^{2} - x + 1

f (x) = x^{5} cos (2 x)

\int_{- 2}^{3} (x^{3} - 6 x) d x

What is derivative of f(x)=(e^x)/(x^2+4),x=1 ?
The answer to derivative of f(x)=(e^x)/(x^2+4),x=1 is (3e)/(25)