What is the derivative of (87x/(99x-87)) ?

The derivative of (87x/(99x-87)) is -(841)/((33x-29)^2)

What is the first derivative of (87x/(99x-87)) ?

The first derivative of (87x/(99x-87)) is -(841)/((33x-29)^2)

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\frac{d}{d x} (\frac{87 x}{99 x - 87})

- \frac{841}{( 33 x - 29 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{87 x}{99 x - 87})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 87 \frac{d}{d x} (\frac{x}{99 x - 87})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 87 \cdot \frac{\frac{d x}{d x} ( 99 x - 87 ) - \frac{d}{d x} ( 99 x - 87 ) x}{( 99 x - 87 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (99 x - 87) = 99

= 87 \cdot \frac{1 \cdot ( 99 x - 87 ) - 99 x}{( 99 x - 87 ) ^{2}}

Simplify

87 \cdot \frac{1 \cdot ( 99 x - 87 ) - 99 x}{( 99 x - 87 ) ^{2}} : - \frac{841}{( 33 x - 29 ) ^{2}}

= - \frac{841}{( 33 x - 29 ) ^{2}}

\frac{s + 1}{s ^{2} - 5 s + 6}

y = x^{3} - 6 x^{2} + 9 x, y = x

\frac{\partial}{\partial x} (- x (x^{2} + y^{2} + z^{2})^{- \frac{3}{2}})

\int 100 - x d x

\int sec^{3} (d) x d x

What is the derivative of (87x/(99x-87)) ?
The derivative of (87x/(99x-87)) is -(841)/((33x-29)^2)
What is the first derivative of (87x/(99x-87)) ?
The first derivative of (87x/(99x-87)) is -(841)/((33x-29)^2)