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Popular >

area y=x^3-6x^2+9x,y=x

Solution

area

y = x^{3} - 6 x^{2} + 9 x, y = x

Solution

8

Solution steps

Apply the area formula:

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x d x

Solve

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x d x : 8

The area is:

= 8

Popular Examples

(\partial)/(\partial x)(-x(x^2+y^2+z^2)^{-3/2})

\frac{\partial}{\partial x} (- x (x^{2} + y^{2} + z^{2})^{- \frac{3}{2}})

integral of 100-x

\int 100 - x d x

integral of sec^3(x

\int sec^{3} (d) x d x

limit as x approaches-(5pi)/2 of sec(x)

x \to - \frac{5 π}{2} lim (sec (x))

(d^2y)/(dt^2)+9y=cos(2t)

\frac{d ^{2} y}{d t ^{2}} + 9 y = cos (2 t)

Frequently Asked Questions (FAQ)

What is area y=x^3-6x^2+9x,y=x ?
The answer to area y=x^3-6x^2+9x,y=x is 8