What is the solution for (d^2y)/(dt^2)+9y=cos(2t) ?

The solution for (d^2y)/(dt^2)+9y=cos(2t) is y=c_{1}cos(3t)+c_{2}sin(3t)+1/5 cos(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dt^2)+9y=cos(2t)

\frac{d ^{2} y}{d t ^{2}} + 9 y = cos (2 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 9 y = cos (2 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

\int \frac{10}{x ^{3} - x ^{2} + 6 x} d x

\int 2 x - 7 d x

\frac{d}{d θ} (- sin (θ))

y = 2 x^{3} - x^{2} + 3, (2, 15)

\frac{1}{2} y^{^{''}} + 2 y = 2 tan (2 t) - \frac{1}{2} e^{3 t}

What is the solution for (d^2y)/(dt^2)+9y=cos(2t) ?
The solution for (d^2y)/(dt^2)+9y=cos(2t) is y=c_{1}cos(3t)+c_{2}sin(3t)+1/5 cos(2t)