What is the solution for (dy)/(dt)-2y=3e^{-2t},y(0)=10 ?

The solution for (dy)/(dt)-2y=3e^{-2t},y(0)=10 is y=-3/(4e^{2t)}+43/4 e^{2t}

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(dy)/(dt)-2y=3e^{-2t},y(0)=10

\frac{d y}{d t} - 2 y = 3 e^{- 2 t}, y (0) = 10

y = - \frac{3}{4 e ^{2 t}} + \frac{43}{4} e^{2 t}

Solution steps

\frac{d y}{d t} - 2 y = 3 e^{- 2 t}

Solve linear ODE:

y = - \frac{3}{4 e ^{2 t}} + \frac{43}{4} e^{2 t}

y = - \frac{3}{4 e ^{2 t}} + \frac{43}{4} e^{2 t}

\frac{\partial}{\partial x} (x^{3} + 2 x^{2} y + x + 2 y)

\int \frac{1}{X ^{2}} D X d X

n = 0 \sum \infty 20000

g (x) = \frac{9 ln ( x )}{4 x + 5}

\int \frac{1}{( 2 x + 1 ) ^{3}} d x

What is the solution for (dy)/(dt)-2y=3e^{-2t},y(0)=10 ?
The solution for (dy)/(dt)-2y=3e^{-2t},y(0)=10 is y=-3/(4e^{2t)}+43/4 e^{2t}