What is the solution for y^'=(x+2y-1)/(x+2y+7) ?

The solution for y^'=(x+2y-1)/(x+2y+7) is y=(4(2\W(1/(16e^{(-9x-c_{1)-8)/(16)}})-1))/3-x/2+1/2

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y^'=(x+2y-1)/(x+2y+7)

y^{^{'}} = \frac{x + 2 y - 1}{x + 2 y + 7}

y = \frac{4 ( 2 W ( \frac{1}{16 e ^{\frac{- 9 x - c _{1} - 8}{16}}} ) - 1 )}{3} - \frac{x}{2} + \frac{1}{2}

Solution steps

y^{'} (x) = \frac{x + 2 y - 1}{x + 2 y + 7}

Solve using substitution:

y = \frac{4 ( 2 W ( \frac{1}{16 e ^{\frac{- 9 x - c _{1} - 8}{16}}} ) - 1 )}{3} - \frac{x}{2} + \frac{1}{2}

y = \frac{4 ( 2 W ( \frac{1}{16 e ^{\frac{- 9 x - c _{1} - 8}{16}}} ) - 1 )}{3} - \frac{x}{2} + \frac{1}{2}

f (x) = 8 x^{3} + 7 x

y^{^{'}} - y = 4

\int (x^{2} - 6 x) d x

x \to 0 lim (h (x))

\int \frac{sin ( x ) cos ( x )}{1 + sin ^{2} ( x )} d x

What is the solution for y^'=(x+2y-1)/(x+2y+7) ?
The solution for y^'=(x+2y-1)/(x+2y+7) is y=(4(2\W(1/(16e^{(-9x-c_{1)-8)/(16)}})-1))/3-x/2+1/2