What is the solution for (dr)/(dθ)=(r^2+8rθ)/(4θ^2) ?

The solution for (dr)/(dθ)=(r^2+8rθ)/(4θ^2) is r(θ)=(4θ^2)/(-θ+c_{1)}

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(dr)/(dθ)=(r^2+8rθ)/(4θ^2)

\frac{d r}{d θ} = \frac{r ^{2} + 8 r θ}{4 θ ^{2}}

r (θ) = \frac{4 θ ^{2}}{- θ + c _{1}}

Solution steps

\frac{d r}{d θ} = \frac{r ^{2} + 8 r θ}{4 θ ^{2}}

Solve Bernoulli ODE:

r (θ) = \frac{4 θ ^{2}}{- θ + c _{1}}

r (θ) = \frac{4 θ ^{2}}{- θ + c _{1}}

y^{^{''}} - y^{^{'}} + 6 y = 0

\frac{d}{d θ} (\frac{4}{2 cos ( θ ) - sin ( θ )})

f (x) = \frac{8 x}{x ^{2} + 1}, (1, 4)

\frac{d}{d x} (\frac{4 x}{3 - tan ( x )})

x \to 0 lim (sin (a x))

What is the solution for (dr)/(dθ)=(r^2+8rθ)/(4θ^2) ?
The solution for (dr)/(dθ)=(r^2+8rθ)/(4θ^2) is r(θ)=(4θ^2)/(-θ+c_{1)}