What is the tangent of 5x-x^2(1.4) ?

The tangent of 5x-x^2(1.4) is y=(5-2.8a_{0})x+1.4a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 5x-x^2(1.4)

tangent of

5 x - x^{2} (1.4)

y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0} - a_{0}^{2} \cdot 1.4)

Find the slope of

y = 5 x - x^{2} 1.4 : \frac{d y}{d x} = 5 - 2.8 x

Compute the slope of

y = 5 x - x^{2} 1.4

x = a_{0} : m = 5 - 2.8 a_{0}

Find the line with slope m=

5 - 2.8 a_{0}

and passing through

(a_{0}, 5 a_{0} - a_{0}^{2} 1.4) : y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

y = (5 - 2.8 a_{0}) x + 1.4 a_{0}^{2}

\frac{\partial}{\partial x} (x^{2} - 4 y^{2})

x \to + 1 lim (x^{3} - 1)

\frac{d ^{2} y}{d x ^{2}} - b y = 0

100 x - \frac{d y}{d x} = x y

cot (x)

What is the tangent of 5x-x^2(1.4) ?
The tangent of 5x-x^2(1.4) is y=(5-2.8a_{0})x+1.4a_{0}^2