What is the limit as n approaches+(-infinity)+of e^n ?

The limit as n approaches+(-infinity)+of e^n is 0

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limit as n approaches+(-infinity)+of e^n

n \to + (- \infty) + lim (e^{n})

0

Solution steps

n \to - \infty lim (e^{n})

Apply the common limit:

n \to - \infty lim (e^{n}) = 0

= 0

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What is the limit as n approaches+(-infinity)+of e^n ?
The limit as n approaches+(-infinity)+of e^n is 0