What is the solution for derivative of f(x)=sqrt(2x-7) ?

The solution for derivative of f(x)=sqrt(2x-7) is f(x)= 1/3 (2x-7)^{3/2}+c_{1}

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derivative of f(x)=sqrt(2x-7)

\frac{d}{d x} f (x) = 2 x - 7

f (x) = \frac{1}{3} (2 x - 7)^{\frac{3}{2}} + c_{1}

Solution steps

\frac{df}{d x} = 2 x - 7

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 2 x - 7 d x

\int 2 x - 7 d x = \frac{1}{3} (2 x - 7)^{\frac{3}{2}} + c_{1}

f (x) = \frac{1}{3} (2 x - 7)^{\frac{3}{2}} + c_{1}

\frac{\partial}{\partial u} (sin (v) cos (u))

\frac{1}{s ^{4} + s ^{3}}

x \to - \infty lim (\frac{8 x ^{2} + 7 x ^{\frac{1}{3}}}{16 x ^{4} + 6})

(cos (t))^{^{'}}

What is the solution for derivative of f(x)=sqrt(2x-7) ?
The solution for derivative of f(x)=sqrt(2x-7) is f(x)= 1/3 (2x-7)^{3/2}+c_{1}