What is the tangent of f(x)=x^2+9,(-5,34) ?

The tangent of f(x)=x^2+9,(-5,34) is y=-10x-16

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tangent of f(x)=x^2+9,(-5,34)

tangent of

f (x) = x^{2} + 9, (- 5, 34)

y = - 10 x - 16

Solution steps

Find the slope of

f (x) = x^{2} + 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 9

(- 5, 34) : m = - 10

Find the line with slope m=

- 10

and passing through

(- 5, 34) : y = - 10 x - 16

y = - 10 x - 16

\int 1 - e^{2 x} d x

1 - x^{2}, 4 - 4 x

\int (3 x + 5)^{4} d x

\frac{d}{d x} (\frac{x ^{3} + 2}{3})

What is the tangent of f(x)=x^2+9,(-5,34) ?
The tangent of f(x)=x^2+9,(-5,34) is y=-10x-16