What is the integral of (sqrt(25x^2-49))/(x^3) ?

The integral of (sqrt(25x^2-49))/(x^3) is -(sqrt(25x^2-49))/(2x^2)+25/14 arcsec(5/7 x)+C

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integral of (sqrt(25x^2-49))/(x^3)

\int \frac{25 x ^{2} - 49}{x ^{3}} d x

- \frac{25 x ^{2} - 49}{2 x ^{2}} + \frac{25}{14} arcsec (\frac{5}{7} x) + C

Solution steps

\int \frac{25 x ^{2} - 49}{x ^{3}} d x

Apply Integration By Parts

: - \frac{25 x ^{2} - 49}{2 x ^{2}} - \int - \frac{25}{2 x 25 x ^{2} - 49} d x

= - \frac{25 x ^{2} - 49}{2 x ^{2}} - \int - \frac{25}{2 x 25 x ^{2} - 49} d x

\int - \frac{25}{2 x 25 x ^{2} - 49} d x = - \frac{25}{14} arcsec (\frac{5}{7} x)

= - \frac{25 x ^{2} - 49}{2 x ^{2}} - (- \frac{25}{14} arcsec (\frac{5}{7} x))

Simplify

= - \frac{25 x ^{2} - 49}{2 x ^{2}} + \frac{25}{14} arcsec (\frac{5}{7} x)

Add a constant to the solution

= - \frac{25 x ^{2} - 49}{2 x ^{2}} + \frac{25}{14} arcsec (\frac{5}{7} x) + C

\frac{d}{d x} (2 x - \frac{2}{x ^{3}})

\int \frac{1 + cos ( x )}{( x + sin ( x ) ) ^{2}} d x

\frac{e ^{x}}{2 x + 1}

y = x^{6} cos (x)

What is the integral of (sqrt(25x^2-49))/(x^3) ?
The integral of (sqrt(25x^2-49))/(x^3) is -(sqrt(25x^2-49))/(2x^2)+25/14 arcsec(5/7 x)+C