What is the limit as x approaches 3 of 2x^2-7x+6 ?

The limit as x approaches 3 of 2x^2-7x+6 is 3

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limit as x approaches 3 of 2x^2-7x+6

x \to 3 lim (2 x^{2} - 7 x + 6)

3

Solution steps

x \to 3 lim (2 x^{2} - 7 x + 6)

Plug in the value

x = 3

= 2 \cdot 3^{2} - 7 \cdot 3 + 6

Simplify

2 \cdot 3^{2} - 7 \cdot 3 + 6 : 3

= 3

\frac{d}{d x} (\frac{n}{x + 1})

\int \frac{1}{x \cdot 1 - x} d x

\frac{1}{( x - 1 )}

sin (x), \frac{π}{4}

y^{^{''}} + 6 y^{^{'}} + 8 y = 4 sin (2 t)

What is the limit as x approaches 3 of 2x^2-7x+6 ?
The limit as x approaches 3 of 2x^2-7x+6 is 3