What is the derivative of cos(3x3) ?

The derivative of cos(3x3) is -9sin(3x)

What is the first derivative of cos(3x3) ?

The first derivative of cos(3x3) is -9sin(3x)

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\frac{d}{d x} (cos (3 x) 3)

- 9 sin (3 x)

Solution steps

\frac{d}{d x} (cos (3 x) \cdot 3)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 3 (- sin (3 x) \cdot 3)

Simplify

= - 9 sin (3 x)

f (x) = x^{2} - x, at x = - 1

\int (a^{2} + x^{2})^{\frac{1}{2}} d x

y^{^{''}} - 8 y^{^{'}} + 9 y = x e^{x}

sin (2 (t - \frac{π}{2}))

x^{2} - 4 x, x - 4

What is the derivative of cos(3x3) ?
The derivative of cos(3x3) is -9sin(3x)
What is the first derivative of cos(3x3) ?
The first derivative of cos(3x3) is -9sin(3x)