What is (\partial)/(\partial x)(2xy+x) ?

The answer to (\partial)/(\partial x)(2xy+x) is 2y+1

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(\partial)/(\partial x)(2xy+x)

\frac{\partial}{\partial x} (2 x y + x)

2 y + 1

Solution steps

\frac{\partial}{\partial x} (2 x y + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (x) = 1

= 2 y + 1

\frac{\partial}{\partial x} (((1 x, 3 y, 4 z)) \cdot (1, 2, 3))

\int sin^{3} (x co) s^{12} x d x

\frac{d}{d x} (arcsin (2^{x}))

y^{^{''}} - 4 y^{^{'}} + 4 y = 1

\int_{0}^{\infty} e^{- s t} d t

What is (\partial)/(\partial x)(2xy+x) ?
The answer to (\partial)/(\partial x)(2xy+x) is 2y+1