What is the derivative of f(x)=x^3-3x ?

The derivative of f(x)=x^3-3x is 3x^2-3

What is the first derivative of f(x)=x^3-3x ?

The first derivative of f(x)=x^3-3x is 3x^2-3

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derivative of

f (x) = x^{3} - 3 x

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

= 3 x^{2} - 3

(x^{2} - 5) (x + 7)

\int sin (11 x) d x

\int_{0}^{2} x^{2} - 4 d x

\frac{\partial}{\partial y} (3 z)

\frac{d}{d x} (\frac{2 sin ( x )}{2 + cos ( x )})

What is the derivative of f(x)=x^3-3x ?
The derivative of f(x)=x^3-3x is 3x^2-3
What is the first derivative of f(x)=x^3-3x ?
The first derivative of f(x)=x^3-3x is 3x^2-3