What is area x/(1+x^2),(x^2)/(1+x^3) ?

The answer to area x/(1+x^2),(x^2)/(1+x^3) is 1/6 ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x/(1+x^2),(x^2)/(1+x^3)

area

\frac{x}{1 + x ^{2}}, \frac{x ^{2}}{1 + x ^{3}}

\frac{1}{6} ln (2)

Decimal Notation

0.11552 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{x}{1 + x ^{2}} - \frac{x ^{2}}{1 + x ^{3}} d x

Solve

\int_{0}^{1} \frac{x}{1 + x ^{2}} - \frac{x ^{2}}{1 + x ^{3}} d x : \frac{1}{6} ln (2)

The area is:

= \frac{1}{6} ln (2)

\frac{d}{d x} (\frac{1}{4} sin (4 x))

n = 1 \sum \infty (\frac{2}{3})^{n - 1}

x \to o lim (f (x))

f (x) = x^{3} - 2 x^{2} - 2 x + 1

\int \frac{1}{( x ^{2} + 7 ) ^{\frac{3}{2}}} d x

What is area x/(1+x^2),(x^2)/(1+x^3) ?
The answer to area x/(1+x^2),(x^2)/(1+x^3) is 1/6 ln(2)