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Popular >

y^'-xyy=2xy

Solution

y^{^{'}} - x yy = 2 x y

Solution

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

y^{'} (x) - x yy = 2 x y

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Popular Examples

integral from-1 to 1 of 1/((1+x^2))

\int_{- 1}^{1} \frac{1}{( 1 + x ^{2} )} d x

integral of 2/((x+2)^2(2-x))

\int \frac{2}{( x + 2 ) ^{2} ( 2 - x )} d x

-12x^2y+y^'=-8x^2

- 12 x^{2} y + y^{^{'}} = - 8 x^{2}

y^{''}+2y^'+y=sin(2x)

y^{^{''}} + 2 y^{^{'}} + y = sin (2 x)

(\partial)/(\partial x)(x-2y^2)

\frac{\partial}{\partial x} (x - 2 y^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'-xyy=2xy ?
The solution for y^'-xyy=2xy is y= 2/(e^{-x^2-c_{1)}-1}