What is (\partial)/(\partial x)(x-2y^2) ?

The answer to (\partial)/(\partial x)(x-2y^2) is 1

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(\partial)/(\partial x)(x-2y^2)

\frac{\partial}{\partial x} (x - 2 y^{2})

1

Solution steps

\frac{\partial}{\partial x} (x - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (r (θ, x) cos (θ))

\int (2 x + 3)^{2} d x

sin (u)

y = 1 + e^{x}

- \frac{2 x}{( x ^{2} + 1 ) ^{2}}

What is (\partial)/(\partial x)(x-2y^2) ?
The answer to (\partial)/(\partial x)(x-2y^2) is 1