What is the derivative of {r}(θ,xcos(θ)) ?

The derivative of {r}(θ,xcos(θ)) is cos(θ) derivative of {r}(θ,x)

What is the first derivative of {r}(θ,xcos(θ)) ?

The first derivative of {r}(θ,xcos(θ)) is cos(θ) derivative of {r}(θ,x)

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\frac{d}{d x} (r (θ, x) cos (θ))

cos (θ) \frac{d}{d x} (r (θ, x))

Solution steps

\frac{d}{d x} (r (θ, x) cos (θ))

Treat

θ

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (θ) \frac{d}{d x} (r (θ, x))

\int (2 x + 3)^{2} d x

sin (u)

y = 1 + e^{x}

- \frac{2 x}{( x ^{2} + 1 ) ^{2}}

y^{^{''}} + 2 y^{^{'}} + \frac{3}{4} y = \frac{3}{4}

What is the derivative of {r}(θ,xcos(θ)) ?
The derivative of {r}(θ,xcos(θ)) is cos(θ) derivative of {r}(θ,x)
What is the first derivative of {r}(θ,xcos(θ)) ?
The first derivative of {r}(θ,xcos(θ)) is cos(θ) derivative of {r}(θ,x)