What is the d/(dt)(cos^3(t)) ?

The d/(dt)(cos^3(t)) is -3cos^2(t)sin(t)

What is the first d/(dt)(cos^3(t)) ?

The first d/(dt)(cos^3(t)) is -3cos^2(t)sin(t)

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\frac{d}{d t} (cos^{3} (t))

- 3 cos^{2} (t) sin (t)

Solution steps

\frac{d}{d t} (cos^{3} (t))

Apply the chain rule:

3 (cos (t))^{2} \frac{d}{d t} (cos (t))

= 3 (cos (t))^{2} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 3 (cos (t))^{2} (- sin (t))

Simplify

= - 3 cos^{2} (t) sin (t)

\frac{d}{d x} ((6 x - 1) (3 x - 5)^{- 1})

\frac{d}{d t} (a cos (3 t))

\frac{\partial}{\partial x} (e^{3 x^{2}} + 4 x y + 5 y^{2})

f (t) = t e^{t}

f (x) = cos (\frac{π x}{2}), at x = 0.7

What is the d/(dt)(cos^3(t)) ?
The d/(dt)(cos^3(t)) is -3cos^2(t)sin(t)
What is the first d/(dt)(cos^3(t)) ?
The first d/(dt)(cos^3(t)) is -3cos^2(t)sin(t)