What is the derivative of 1/(2y) ?

The derivative of 1/(2y) is -1/(2y^2)

What is the first derivative of 1/(2y) ?

The first derivative of 1/(2y) is -1/(2y^2)

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derivative of

\frac{1}{2 y}

- \frac{1}{2 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{1}{2 y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot y^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot y^{- 1 - 1}) : - \frac{1}{2 y ^{2}}

= - \frac{1}{2 y ^{2}}

\frac{16}{( 5 - x ) ^{2}} - 1

\frac{\partial}{\partial x} (arcsin (3 x - 2))

f (x) = \frac{x}{x ^{2} - 16}

x \to 1 lim (\frac{x}{1 - x ^{4}})

y = \frac{40}{x}, y = - 9 x + 39

What is the derivative of 1/(2y) ?
The derivative of 1/(2y) is -1/(2y^2)
What is the first derivative of 1/(2y) ?
The first derivative of 1/(2y) is -1/(2y^2)