What is the solution for t^2(dy)/(dt)+4ty-y^3=0,y(1)= 3/(sqrt(2)) ?

The solution for t^2(dy)/(dt)+4ty-y^3=0,y(1)= 3/(sqrt(2)) is y=(3sqrt(t))/(sqrt(2))

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t^2(dy)/(dt)+4ty-y^3=0,y(1)= 3/(sqrt(2))

t^{2} \frac{d y}{d t} + 4 t y - y^{3} = 0, y (1) = \frac{3}{2}

y = \frac{3 t}{2}

Solution steps

t^{2} \frac{d y}{d t} + 4 t y - y^{3} = 0

Solve Bernoulli ODE:

y = \frac{3 t}{2}

y = \frac{3 t}{2}

y = \frac{3}{sin ( x ) + cos ( x )}

\int \frac{48}{36 - x ^{2}} d x

\frac{d}{d x} (\frac{( x + b ) ( x - a )}{( x - b )})

f (x) = 4 x + 84, (4, 10)

\frac{d ^{2}}{d x ^{2}} (2^{(x^{2} + 1)})

What is the solution for t^2(dy)/(dt)+4ty-y^3=0,y(1)= 3/(sqrt(2)) ?
The solution for t^2(dy)/(dt)+4ty-y^3=0,y(1)= 3/(sqrt(2)) is y=(3sqrt(t))/(sqrt(2))