What is the derivative of 3x^2-3x ?

The derivative of 3x^2-3x is 6x-3

What is the first derivative of 3x^2-3x ?

The first derivative of 3x^2-3x is 6x-3

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\frac{d}{d x} (3 x^{2} - 3 x)

6 x - 3

Solution steps

\frac{d}{d x} (3 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

= 6 x - 3

(y^{3} - x y^{2}) d x + 2 x^{2} y d y = 0

(a^{3})^{^{'}}

x \to 4 lim (6 - 3 x)

\frac{d}{d x} (c cos (t) + t^{2}, t)

\frac{d}{d x} (arcsec (e^{3 x}))

What is the derivative of 3x^2-3x ?
The derivative of 3x^2-3x is 6x-3
What is the first derivative of 3x^2-3x ?
The first derivative of 3x^2-3x is 6x-3