What is the tangent of y=(1+x)/(1+e^x),(0, 1/2) ?

The tangent of y=(1+x)/(1+e^x),(0, 1/2) is y= 1/4 x+1/2

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tangent of y=(1+x)/(1+e^x),(0, 1/2)

tangent of

y = \frac{1 + x}{1 + e ^{x}}, (0, \frac{1}{2})

y = \frac{1}{4} x + \frac{1}{2}

Solution steps

Find the slope of

y = \frac{1 + x}{1 + e ^{x}} : \frac{d y}{d x} = \frac{1 - e ^{x} x}{( 1 + e ^{x} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(0, \frac{1}{2}) : y = \frac{1}{4} x + \frac{1}{2}

y = \frac{1}{4} x + \frac{1}{2}

x \to 0 + lim (3 x ln (x))

3 x ln (15 x)

1 = - sin (x - y) \frac{d}{d x} (x - y)

x \to 6 lim (\frac{2 x + 7}{x + 3})

x^{2} + 2 x + 1, 2 x + 5, [- 2, 2]

What is the tangent of y=(1+x)/(1+e^x),(0, 1/2) ?
The tangent of y=(1+x)/(1+e^x),(0, 1/2) is y= 1/4 x+1/2