What is the derivative of x/(3sqrt(x^2+1))-1/8 ?

The derivative of x/(3sqrt(x^2+1))-1/8 is 1/(3(x^2+1)sqrt(x^2+1))

What is the first derivative of x/(3sqrt(x^2+1))-1/8 ?

The first derivative of x/(3sqrt(x^2+1))-1/8 is 1/(3(x^2+1)sqrt(x^2+1))

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derivative of

\frac{x}{3 x ^{2} + 1} - \frac{1}{8}

\frac{1}{3 ( x ^{2} + 1 ) x ^{2} + 1}

Solution steps

\frac{d}{d x} (\frac{x}{3 x ^{2} + 1} - \frac{1}{8})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{3 x ^{2} + 1}) - \frac{d}{d x} (\frac{1}{8})

\frac{d}{d x} (\frac{x}{3 x ^{2} + 1}) = \frac{1}{3 ( x ^{2} + 1 ) x ^{2} + 1}

\frac{d}{d x} (\frac{1}{8}) = 0

= \frac{1}{3 ( x ^{2} + 1 ) x ^{2} + 1} - 0

Simplify

= \frac{1}{3 ( x ^{2} + 1 ) x ^{2} + 1}

x \to 3 - lim (\frac{( x ^{2} )}{x - 3})

\frac{\partial}{\partial t} (\frac{t}{2})

\frac{d}{d x} (2 x^{3} - 6)

\frac{d}{d x} (24 x + sin (x))

f (x) = arcsin (2 x)

What is the derivative of x/(3sqrt(x^2+1))-1/8 ?
The derivative of x/(3sqrt(x^2+1))-1/8 is 1/(3(x^2+1)sqrt(x^2+1))
What is the first derivative of x/(3sqrt(x^2+1))-1/8 ?
The first derivative of x/(3sqrt(x^2+1))-1/8 is 1/(3(x^2+1)sqrt(x^2+1))