What is the derivative of e^{2ln(3x}) ?

The derivative of e^{2ln(3x}) is 18x

What is the first derivative of e^{2ln(3x}) ?

The first derivative of e^{2ln(3x}) is 18x

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\frac{d}{d x} (e^{2 l n (3 x)})

18 x

Solution steps

\frac{d}{d x} (e^{2 l n (3 x)})

Simplify

e^{2 l n (3 x)} : 9 x^{2}

= \frac{d}{d x} (9 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 2 x^{2 - 1}

Simplify

= 18 x

6 y

sin (x) ln (x^{2} + 1)

x \to 2 lim (\frac{3 x}{x - 2})

\int \frac{3}{4} sec (x) tan (x) d x

tan (2 x + 3)

What is the derivative of e^{2ln(3x}) ?
The derivative of e^{2ln(3x}) is 18x
What is the first derivative of e^{2ln(3x}) ?
The first derivative of e^{2ln(3x}) is 18x