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Popular >

integral from 0 to 1 of (x^3-1)

Solution

\int_{0}^{1} (x^{3} - 1) d x

Solution

- \frac{3}{4}

+1

Decimal

- 0.75

Solution steps

\int_{0}^{1} x^{3} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x - \int_{0}^{1} 1 d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 1 d x = 1

= \frac{1}{4} - 1

Simplify

\frac{1}{4} - 1 : - \frac{3}{4}

= - \frac{3}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x^3-1) ?
The integral from 0 to 1 of (x^3-1) is -3/4