What is the derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 ?

The derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 is 10x^4-24x^3+12x^2+8x-6

What is the first derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 ?

The first derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 is 10x^4-24x^3+12x^2+8x-6

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\frac{d}{d x} (2 x^{5} - 6 x^{4} + 4 x^{3} + 4 x^{2} - 6 x + 2)

10 x^{4} - 24 x^{3} + 12 x^{2} + 8 x - 6

Solution steps

\frac{d}{d x} (2 x^{5} - 6 x^{4} + 4 x^{3} + 4 x^{2} - 6 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{5}) - \frac{d}{d x} (6 x^{4}) + \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{5}) = 10 x^{4}

\frac{d}{d x} (6 x^{4}) = 24 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (2) = 0

= 10 x^{4} - 24 x^{3} + 12 x^{2} + 8 x - 6 + 0

Simplify

= 10 x^{4} - 24 x^{3} + 12 x^{2} + 8 x - 6

\int (x - 2) d x

\frac{d}{d x} (\frac{3 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}})

y^{^{''}} + 2 y^{^{'}} + y = - 2 e^{x}

\frac{d y}{d x} = \frac{x - 4}{y - 6}

\int_{1}^{2} \frac{5}{x ^{3} + 2 x} d x

What is the derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 ?
The derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 is 10x^4-24x^3+12x^2+8x-6
What is the first derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 ?
The first derivative of 2x^5-6x^4+4x^3+4x^2-6x+2 is 10x^4-24x^3+12x^2+8x-6