What is the tangent of f(x)= 1/((2x-1)^6),\at x=1 ?

The tangent of f(x)= 1/((2x-1)^6),\at x=1 is y=-12x+13

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tangent of f(x)= 1/((2x-1)^6),\at x=1

tangent of

f (x) = \frac{1}{( 2 x - 1 ) ^{6}}, at x = 1

y = - 12 x + 13

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{( 2 x - 1 ) ^{6}} : \frac{df ( x )}{d x} = - \frac{12}{( 2 x - 1 ) ^{7}}

Compute the slope of

f (x) = \frac{1}{( 2 x - 1 ) ^{6}}

x = 1 : m = - 12

Find the line with slope m=

- 12

and passing through

(1, 1) : y = - 12 x + 13

y = - 12 x + 13

x \to - 2 lim (8 + x^{3})

\frac{d}{d a} (\frac{cos ^{2} ( a )}{1 - sin ( a )})

\int 10 + 6 x + 36 x^{2} d x

\int 1 - \frac{x ^{2}}{16} d x

y x \frac{d y}{d x} = \frac{sec ( 3 y )}{1 + x}

What is the tangent of f(x)= 1/((2x-1)^6),\at x=1 ?
The tangent of f(x)= 1/((2x-1)^6),\at x=1 is y=-12x+13