What is the integral of ln(17t) ?

The integral of ln(17t) is tln(17t)-t+C

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integral of ln(17t)

\int ln (17 t) d t

t ln (17 t) - t + C

Solution steps

\int ln (17 t) d t

Apply Integration By Parts

: t ln (17 t) - \int 1 d t

= t ln (17 t) - \int 1 d t

\int 1 d t = t

= t ln (17 t) - t

Add a constant to the solution

= t ln (17 t) - t + C

\frac{d}{d x} (\frac{7}{5} sin^{2} (2 x))

\int sec^{2} (2 x - 1) d x

y (x - y - 2) d x + x (y - x + 4) d y = 0

e^{2} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

(- 4, 7), (- 6, - 4)