What is the integral from-24 to 0 of 1/(sqrt(25-x)) ?

The integral from-24 to 0 of 1/(sqrt(25-x)) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-24 to 0 of 1/(sqrt(25-x))

\int_{- 24}^{0} \frac{1}{25 - x} d x

4

Solution steps

\int_{- 24}^{0} \frac{1}{25 - x} d x

Apply u-substitution

: \int_{49}^{25} - \frac{1}{u} d u

= \int_{49}^{25} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{25}^{49} - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{25}^{49} \frac{1}{u} d u)

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{25}^{49}

= - (- [2 u^{\frac{1}{2}}]_{25}^{49})

Simplify

- (- [2 u^{\frac{1}{2}}]_{25}^{49}) : [2 u]_{25}^{49}

= [2 u]_{25}^{49}

Compute the boundaries:

4

= 4

2 x^{2} + x y + 2 y^{2} = 5

\frac{d}{d t} (e^{6 t s i n (2 t)})

\frac{d}{d x} ((2^{x})^{8})

f (t) = 2 t

2 x^{5} - 3 e^{6 x}

What is the integral from-24 to 0 of 1/(sqrt(25-x)) ?
The integral from-24 to 0 of 1/(sqrt(25-x)) is 4